(w^2-(3w+2))/(5-5w^2)

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Solution for (w^2-(3w+2))/(5-5w^2) equation: 


D( w )

5-(5*w^2) = 0

5-(5*w^2) = 0

5-(5*w^2) = 0

5-5*w^2 = 0

-5*w^2 = -5 // : -5

w^2 = 1

w^2 = 1 // ^ 1/2

abs(w) = 1

w = 1 or w = -1

w in (-oo:-1) U (-1:1) U (1:+oo)

(w^2-(3*w)-2)/(5-(5*w^2)) = 0

(w^2-3*w-2)/(5-5*w^2) = 0

w^2-3*w-2 = 0

w^2-3*w-2 = 0

DELTA = (-3)^2-(-2*1*4)

DELTA = 17

DELTA > 0

w = (17^(1/2)+3)/(1*2) or w = (3-17^(1/2))/(1*2)

w = (17^(1/2)+3)/2 or w = (3-17^(1/2))/2

(w-((3-17^(1/2))/2))*(w-((17^(1/2)+3)/2)) = 0

((w-((3-17^(1/2))/2))*(w-((17^(1/2)+3)/2)))/(5-5*w^2) = 0

( w-((17^(1/2)+3)/2) )

w-((17^(1/2)+3)/2) = 0 // + (17^(1/2)+3)/2

w = (17^(1/2)+3)/2

( w-((3-17^(1/2))/2) )

w-((3-17^(1/2))/2) = 0 // + (3-17^(1/2))/2

w = (3-17^(1/2))/2

w in { (17^(1/2)+3)/2, (3-17^(1/2))/2 }

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